(2x^2+3x-5)(x+2)=

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Solution for (2x^2+3x-5)(x+2)= equation: 


Simplifying
(2x2 + 3x + -5)(x + 2) = 0

Reorder the terms:
(-5 + 3x + 2x2)(x + 2) = 0

Reorder the terms:
(-5 + 3x + 2x2)(2 + x) = 0

Multiply (-5 + 3x + 2x2) * (2 + x)
(-5(2 + x) + 3x * (2 + x) + 2x2 * (2 + x)) = 0
((2 * -5 + x * -5) + 3x * (2 + x) + 2x2 * (2 + x)) = 0
((-10 + -5x) + 3x * (2 + x) + 2x2 * (2 + x)) = 0
(-10 + -5x + (2 * 3x + x * 3x) + 2x2 * (2 + x)) = 0
(-10 + -5x + (6x + 3x2) + 2x2 * (2 + x)) = 0
(-10 + -5x + 6x + 3x2 + (2 * 2x2 + x * 2x2)) = 0
(-10 + -5x + 6x + 3x2 + (4x2 + 2x3)) = 0

Combine like terms: -5x + 6x = 1x
(-10 + 1x + 3x2 + 4x2 + 2x3) = 0

Combine like terms: 3x2 + 4x2 = 7x2
(-10 + 1x + 7x2 + 2x3) = 0

Solving
-10 + 1x + 7x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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